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WeeG
02-17-2010, 11:03 AM
hi guys, I seem to forgot how it's done, a little help will be appreciated !

the number of accidents in a factory have the Poisson distribution with a mean of 2.0225 accidents a day.

a. what is the probability that during 3 working days in a row, the general number of accidents will be 2 or bigger than 2 ?
b. calculate the probability that in a working week of 5 days, there will be exactly 3 days with maximum of 1 accident.

cheers !

vinux
02-17-2010, 11:30 AM
Hint:
a. if X1,X2,X3 are Poisson rv. with mean lambda, then X1+X2+X3 follows Poisson with mean 3*lambda
b. p= Probability of maximum of 1 accident=P(X <=1). then use Binomial distribution

WeeG
02-17-2010, 04:04 PM
thank you, your hint helped !