If probability A and B are 0.5 each, how do you find that a probability of A is more than three times the P(B)?

Do you simply do: P(A)^3?

I'm not sure I'm following - could you re-state this?

The problem states that:

"If a parachutist lands a random point between markers A and B, find the probability that he is closer to A than B. Find the probability that his distance to A is more than three times his distance to B."

So, P(A) is .5 and P(B) is .5 right? But I'm just not sure by finding the second question.

Since two points A and B can be connected by a straight line, the parachutist can land anywhere on the line.

Now, for example, if you divide the line exactly in half (into 2 segments), then there is a 0.5 probability that the parachutist will land on the segment closer to A, and a 0.5 probability that the parachutist will land on the segment closer to B.

In order to answer this question, you need to envision the line broken up into 4 equal segments. The probability that the parachutist lands on the segment closest to B is 1/4 or 0.25. Since landing on this segment will place him/her more than 3 times further from A than B, then the answer is 0.25.