How in the world does one do a probability problem on minitab?? I've completely forgotten and have spent hours today trying to figure it out! Minitab final is tomorrow and this is the one topic I just can't do. Help! I've written a sample of what I'm attempting below. Greatly need the commands. I'm missing something in the process, somewhere.

If it helps, I have minitab 15.

A machine is set to fill 1 liter milk botles. The fills are normally distributed with a mean of 1.04 liters and a standard deviation of .05 liters.

A. What percent of the bottles will have more than 1 liters of milk?

B. Find the value below which the smallest 10% of the fills occurs.

What I "think" I know: need to find P (x>1.oL), which is the same as 1- P(x<1.0L) So far so good?

Commands for the progam: Calc--probability--normal

This is where I get into trouble. It asks for inputs. Now what??

How in the world does one do a probability problem on minitab?? I've completely forgotten and have spent hours today trying to figure it out! Minitab final is tomorrow and this is the one topic I just can't do. Help! I've written a sample of what I'm attempting below. Greatly need the commands. I'm missing something in the process, somewhere.

If it helps, I have minitab 15.

A machine is set to fill 1 liter milk botles. The fills are normally distributed with a mean of 1.04 liters and a standard deviation of .05 liters.

A. What percent of the bottles will have more than 1 liters of milk?

B. Find the value below which the smallest 10% of the fills occurs.

What I "think" I know: need to find P (x>1.oL), which is the same as 1- P(x<1.0L) So far so good?

Commands for the progam: Calc--probability--normal

This is where I get into trouble. It asks for inputs. Now what??



A. How about setting Mean=1.04 and Std.=0.05. Then click cumulative probability (by default). Under "input constant" enter 1.0.

Output: p=.211855, thus, 1-.211855 = .788145 or 78.8145% of the bottles will have more than 1 litre.

B. With Mean=1.04 and Std.=0.05, click inverse cumulative probability. Under "input constant" enter 0.10

Output: X=0.975922 is the value (litre) where 10% of the bottles will fall below this value.


How's that?