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summertigger
01-22-2006, 04:40 PM
In a normal distribution with u=200 and o=30 find the percentage of values that are between 180 and 195.

If I could get an example of this that would be great Thanks!

summertigger
01-22-2006, 07:53 PM
Did I do this right?
z=(180-200)/30= -.67
= .2486

Z=(195-200)/30= -.17
=.0675

=.2486-.0675
=.1811

=18%