A mail order company receives an average of five orders per 500 solicitations. If it sends out 100 advertisements, find the probability of receiving at least two orders. Use the poisson distribution.

(a).9048
(b).1839
(c).2642
(d).9596


Can anyone help me figure this problem out please!

Hi carebear,

Welcome to TS. You'll need to use the Poisson probability function. The mean for the Poisson distribution is 1 since you are only sending 100 ads. And P(X>=2) = 1-P(X=0)-P(X=1)

i've tried to figure this out but i'm not sure if the average is 5 because then i still can't get one of those answers that are given

so it would be d then right because you have to do 1-.041.

The mean is 1, since they only sent out 100 solicitations (remember, the original rate given was 5 per 500, so that translates to 1 per 100).

To find P(x >= 2), you need to find P(x=0) and P(x=1), add them together, then subtract that sum from 1.