I hope you can help me out to figure what I am doing wrong... I have the answer to the exercise and I don't get how I find something completely different.

The informations I have :

Sample mean X=19,1 / Sample SD S=6 / Sample Size N= 344

Population n= 5 800

Question: If population mean is 18,5 what is P(X(bar)>19,1)

If population mean is 18,5 than sample mean is the same.

Thus: P(X(bar)>19,1)=P(Z>(19,1-18,5)/6)=P(Z>0,1)

P(Z>0,1)=1-P(Z<0,1)

In my table Z=0,1 is P=0,54

Thus P(Z>0,1)= 0,46

But the answer I have is 0.0322...

Can you help me ? What is wrong in my calculations ?

Thanks a lot !! ]]>

a) A one-tailed t-test when P=0.063 for the two tailed T-test (I think this is accept)

b)A kruskall-wallis test when P=0.0036 (I think this is reject)

c)A Mann Whitney test reported as P > 0.05. (I think this is accept)

d)A matched pairs t-test, with calculated t = 3.5, tabulated t = 2.1 at P = 0.05. (I think this is reject)

e)A Kruskal-Wallis test, with calculated value = 11.3 tabulated value = 9.9 at P = 0.05. (I think this is reject)

f) A Z-test reported as P = 0.50, if the decision was based on P = 0.05. (I think this is reject)

g)A Kolmogorov-Smirnov 1-sample test reported with P = 0.325. (I think this is accept)

h)A 1-sample t-test, with calculated t = 7.2 and tabulated t = 2.7 at P = 0.05.(I think this is reject)

i) A matched pairs t-test, with calculated t = 3.5, tabulated t = 2.1 at P = 0.05.(I think this is reject)

j) A Wilcoxon matched pairs test with calculated value = 8.0 and tabulated value = 8.0 at P = 0.05. (I think this is accept)

k) A Mann Whitney reported as P < 0.05. (I think this is reject)

Thanks so much for your help!

Bryony ]]>

I'm no expert in statistics and the answers might be really simple.

I would really appreciate if someone could explain this to me as I'm considering using it in an assignment (Im studying social science, not statistics)

http://worldhappiness.report/wp-cont...17/03/HR17.pdf

Thank you ]]>