proc iml;
S = 10;
N = 100;
P = 5000;
call randseed(12345);
Res = {0 , 0};
do rep = 1 to S;
X = j(N, P, .);
Y = j(N, 2, .);
call randgen(x, ’normal’);
call randgen(y, ’normal’);
Cor = corr(Y || X)[{1 2}, 3:(P+2)];
Res = Res + abs(Cor)[ ,<>];
end;
Res = Res / S;
print Res;
quit...