Reply With Quote(A) P(both) = 0.6 * 0.6 = 0.36
(B) P(at least 1) = 1 - P(neither) = 1 - (0.4 * 0.4) = 0.84
(C) P(exactly 1) = 1 - [ P(both) + P(neither) ] = 1 - [ 0.36 + 0.16 ] = 0.48
[Question]
A survey by the Canadian frequent flyers association revealed that
60% of its members made independent airline reservations last year.
If two members are selected at random, what is the probability that.
A) both made reservations last year ?
b) at least one made a reservation last year?
c) Only one made a reservation last year?
[Difficulty]
Im jsut very confused and dont know where to go. Ive been working
this problem for a week and i dont know if im on the right track. I
havent taken math in over 10 yrs.
[Thoughts]
A)60X60= 36
B)18/60=30
I dont know if im on the right track at all. just need some help pls
(A) P(both) = 0.6 * 0.6 = 0.36
(B) P(at least 1) = 1 - P(neither) = 1 - (0.4 * 0.4) = 0.84
(C) P(exactly 1) = 1 - [ P(both) + P(neither) ] = 1 - [ 0.36 + 0.16 ] = 0.48
Thank you very much for your help
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