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Thread: how to solve this???

  1. #1
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    Question how to solve this???



    An exam starts at t=0 & is supposed to be over at t=3.The students are asked to "wrap it up" at t=2.5.The relative number of students finishing an exam at time t is given in a graph(normalized).The function f(t) is approximated as:
    f(t)=8/55 ,0<t<2.5
    (204t-502)/55 ,2.5<t<3
    -20t+62 , 3<t<3.1
    Define outcomes and events.

    -Im thinking that IF the outcomes are:8/55,(204t.....,-20...
    Then would the events be only those at t=2.5???

  2. #2
    Bhoot
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    Re: how to solve this???

    This is a continuous distribution. probability at t=2.5 doesn't make sense. Only the probability at some interval make sense.
    In the long run, we're all dead.

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    Ninja say what!?!
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    Re: how to solve this???

    Quote Originally Posted by vinux View Post
    This is a continuous distribution. probability at t=2.5 doesn't make sense. Only the probability at some interval make sense.
    Yes. What f(t) is telling you is the probability of a student finishing between each time point.

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    Re: how to solve this???

    can i say the events are: {0<t<2.5},{2.5<t<3},{3<t<3.1} ?

  5. #5
    Bhoot
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    Re: how to solve this???


    In continuous case you can define events in many ways.

    You can take the following event
    A_s =(0,s)
    P(A_s) = Probability that finishing exam within s time.

    Here P(A_s) =F(s) same as the cumulative distribution function
    In the long run, we're all dead.

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