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hint:
Since it is symmetric on both axis.. you can focus on first quadrant. Take one variable as free and other is depending on the free variable..
Two RVs X & Y have the jiont density: f(x,y)=a, x^2+y^2<=1
Find the constant a.
>>> HOW CAN I SOLVE THIS ???can i say that z=x^2+y^2
hint:
Since it is symmetric on both axis.. you can focus on first quadrant. Take one variable as free and other is depending on the free variable..
In the long run, we're all dead.
can u plz explain for me how to put the limits, should i put each in terms of the other???
You are confusing yourself by thinking this is a complicated problem.
The probablity density is just a constant, so this is a simple, uniform distribution over a region of the (x,y) plane. The equation x^2 + y^2 <= 1 is just defining that region. Just figure out what the region looks like.
There is no calculus involved here. There is no math beyond elementary school.
You learned the equation of a circle in elementary school? Impressive...Originally Posted by ichbin
Once you know that
represent a unit disc, then
is just the reciprocal of the area of a unit disc.
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