Are you sure about the first one. What is the distribution of sum of two independent Poisson random variables?
I got a question.
Q) Let {X(t), t>=0} and {Y(t), t>=0} be independent Poisson processes with parameterand
respectively. Define
= X(t) + Y(t) and
= X(t) - Y(t) and
= X(t) + k, k a positive integer. Determine which of the above are Poisson and find lambda.
so I figured thatis limiting case to the Binomial distribution and the lambda is (
)/(
+
)
and for, it is Skellam distribution and lambda is
-
and for, even though you add positive integer k to poisson process, you get
+ k.
I not sure that this is right...
I got the idea from the internet (except for the last one).
and for, there is no lambda?
b/c Binomial distribution doesn't have mean.
Please tell me what I did wrong.
Thank you....
Are you sure about the first one. What is the distribution of sum of two independent Poisson random variables?
In the long run, we're all dead.
I actually found that the mean of binomial distribution is number of trial * success probability in each trial, so this is lambda...
how about Z2 and Z3? are they okay?
Last edited by jjangub; 11-03-2010 at 08:31 PM.
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