The percentage of University of Illinois students that have taken either Economics 102 or 103 is 85 %. Suppose random samples of 225 students are taken. Find the value where 1% of the sample proportions are greater than that value.
I need help understanding the last part of this problem and how I can use it in the formula. Thanks
In what formula?Originally Posted by Xtreme11
Do you imply: X = S*Z + M ??
where M and S are the mean and standard deviation associated with the data (Binomial)?...M=N*p and S=Sqrt[N*p*q], and, Z is the critical value at .01 from the unit normal distribution (upper tail region)?
The formula I was thinking of was p(1-p)/n but I dont think that will work. The 1% part of the problem is giving me trouble. Could you explain what you mean on the last part of what you wrote about Z being the critical value at
.01.....? Thanks
Well, think of the standard normal (Z) distribution. The proportion of the area under the curve that lies above Z=2.32635 is 0.01.
Can you tell me the right formula to use because I think I had the wrong one in mind?Thanks
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