Yes, you are correct
Assume that the number of faults in the roll, say y, follows a Poisson distribution with rate lambda*x, where x is the length of the roll.
Does this mean the pmf is
f(y; lambda*x) = exp(-lambda*x)(lambda*x)^y / y! ?
Thanks
Yes, you are correct
Thanks!!
So if lambda follows a Gamma distribution with shape and scale parameters alpha and beta, how do I go about finding the distribution of y (which follows the Poisson distribution with rate lamba*x) ?
Thanks again!
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