Use the binomial distribution.
SUM(C(10,k)p^(k)q^(10-k)), k=0..3
=C(10,0)p^(0)q^(10)+C(10,1)pq^9+C(10,2)p^2q^8+C(10,3)p^3q^7
p=1/2 and q=1/2
Assume that male and female births are equally likely and that the birth of any child does not affect the probability of the gender of any other children. Find the probability of at most three boys in ten births.
Please help me I don't get it.
Use the binomial distribution.
SUM(C(10,k)p^(k)q^(10-k)), k=0..3
=C(10,0)p^(0)q^(10)+C(10,1)pq^9+C(10,2)p^2q^8+C(10,3)p^3q^7
p=1/2 and q=1/2
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