Hi Mechalus, I'm </rolls dice> happy to try to help you.

I think your problem becomes a lot clearer if you look at it the right way; instead of working out all the situations where you succeed, try calculating when you fail.

The idea is P(succeed) = 1 - P(fail)

Fail Event = both dice roll < 3

P(die #1 roll < 3) = 2/6, P(die #2 roll < 3) = 2/6

So P(fail) = P(die #1 roll < 3) AND P(die #2 roll < 3) = (2/6) * (2/6) = 1/9

So P(succeed) = 8/9 (should be higher than 67% right?)

Fail Event = both dice roll < 3

P(die #1 roll < 3) = 2/6, P(die #2 roll < 3) = 2/8

So P(fail) = (2/6) * (2/8) = 1/12

So P(succeed) = 11/12 (should be higher than 75% right?)