Reply With QuoteIt's a binomial distribution problem, with p=.38 and n=6.
Equation needed
I've been at this question for an hour, going through my notes and I just can't find the right way to do this question: According to a recent study, 38% of all women will suffer a hip fracture because of osteoporosis by the age of 85. If six women aged 85 are randomly selected, what is the probability that:
a. none of them will suffer (or has suffered) a hip fracture due to osteoporosis?
b. At least four of them will suffer a fracture
c. fewer than 2 will suffer.
I don't know any other way to figure this out other than tree diagram maybe but that would take way too long.
If anyone knows how to solve this please tell me.
It's a binomial distribution problem, with p=.38 and n=6.
what formula should I use for this the above question???
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