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Thread: Help with P-value problem

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    Help with P-value problem




    I need help solving this problem

    Find the P-value for the indicated hypothesis test. An airline claims that the no-show rate for passengers booked on its flights is less than 6%. OF 380 randomly selected reservations, 18 were no-shows. Find the P-value for a test of the airline's claim.

    This is what I did below but I got the wrong answer

    18/380 = 0.05 1 - .06 = .94

    I looked up 0.05 on the z score table and came up with .5199

    .5199 - .06 = 0.4599

    (.06) (.94) / 380 = .00015

    square root of .00015 = .012

    0.4599/.012 = 38.3

  2. #2
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    Nevermind, I figured this problem out.

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