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Thread: Var(X1 + X2 +...) = Var(X1) + Var(X2) +...?

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    Var(X1 + X2 +...) = Var(X1) + Var(X2) +...?



    Suppose the random variables {X_i} are independent,
    then is it always true that Var(X_1 + X_2 + X_3 +...) = Var(X_1) + Var(X_2) + Var(X_3)+...?


    Note that I'm talking about the case of

    Σ X_i
    i=1

    I'm sure it's true for finite series, but how about infinite series?
    I tried searching the internet, but can't find anything...

    Any help is appreciated!

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    Re: Var(X1 + X2 +...) = Var(X1) + Var(X2) +...?

    I think you need to require the sum of random variables converge to a random variable
    with finite variance. But I am not sure the necessary/sufficient condition for it to hold.
    It is just my guess.

  3. #3
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    Re: Var(X1 + X2 +...) = Var(X1) + Var(X2) +...?

    I believe this theorem will do (it's a basis for the strong law of large numbers).


    If we let \left \{ x_{n} \right \}_{n=1}^{\infty } be a sequence of independent random variables where E\left ( x_{n} \right )=0 for all n\in\mathbb{N} and where

    \sum_{n=1}^{\infty }E\left ( x_{n}^{2} \right )< \infty.

    Then (the sum) S_{n} converges almost surely to a limit S.

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    Re: Var(X1 + X2 +...) = Var(X1) + Var(X2) +...?


    First, type of convergence of { Un } should be clarified , if we denote Un = X1+X2+…..+Xn+ …

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