f(x,y) = (1/4)xy if 0<x<2, 0<y<2
= 0 otherwise
how to find P(XY<2)?
I wrote it out as ∫(from 2 to 0) ∫(from (2/x) to 0) (1/4)xy dy dx,
but my answers never worked out.
I think the problem lies in integrating from what to what, but I'm not sure how to correct the mistake. Please help! Thanks!