You said one thing, that makes me want to make sure about the rules of the game; do you have to keep at least one tossed die? You said you want to come up with odds for scores all the way down to 4, but isn't it possible to get 0 if you don't get a 2 and a 4?

I'm trying to calculate the probably of getting a 24, and that's a beast calculation. I'm trying to think of the probability of getting a 24, using {# of ways to get 24} / {# of all possibilities}, and the # of all possibilities isn't so easy to get.

Let's say you throw six 6's first. Do you keep four of the 6's, and take a chance that you'll get a 2 or 4 (or, 2 and 4 if you're extra lucky) out of just two dice on the next throw, and then the last required throw? Or keep just one of the 6's, so you have more chance to get the 2 and 4 you need in order to score anything? To get the # of all possibilities, we'd have to count all these different strategies. And that's just if you get six 6's first.