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Thread: Mean of a Joint Random Variable

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    Mean of a Joint Random Variable



    I am new to statistics, so bare with me please.
    I have the following question to answer.

    Suppose X and Y have joint density

    f(x, y) = \left\{
  \begin{array}{l l}
    3x & \quad 0 \leq x \leq y \leq 1\\
    3y & \quad 0 \leq y \leq x \leq 1\\
    0 & \quad \text{otherwise}
  \end{array} \right.

    Find the mean of Y.

    As I understand it, I need to do the following to find the mean of Y
    \int_{-\infty}^{\infty}\int_{-\infty}^{\infty}yf(x, y)dxdy

    My problem is with the limits of integration. Am I correct to assume that I need to split this double integral up into 2 double integrals and add them together? To this effect I have come up with
    \int_{0}^{1}\int_{0}^{y}3xydxdy + \int_{0}^{1}\int_{0}^{x}3y^{2}dxdy

    Is this what I want to do?

    Thanks for your help.

    Bidski

  2. #2
    RotParaTon
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    Re: Mean of a Joint Random Variable

    Your second integral doesn't quite make sense. If you're integrating with respect to x first then you shouldn't have x as one of your integration limits.
    "His programming is malfunctioning. It begins! Get your weapons, he's going to become a killbot!!!" - bryangoodrich

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    Bidski (08-23-2012)

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    Re: Mean of a Joint Random Variable

    Oops, sorry. That part is a typo. It should be dydx for the second double integal.

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    RotParaTon
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    Re: Mean of a Joint Random Variable

    Ah - then it looks good to me.
    "His programming is malfunctioning. It begins! Get your weapons, he's going to become a killbot!!!" - bryangoodrich

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    Bidski (08-23-2012)

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    Re: Mean of a Joint Random Variable


    Cool, thanks for the confirmation.

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