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Give it a try and tell us if you think the result is a valid probability.
I have a question.
The question below asks me Calculate the probability the coin comes up heads at least one time..
So it becomes 1- 15!/15!0! etc etc.
My question us, if the question asked me if the coin came up at least 4 times, would I subtract 4- 15!/!5! 0!... Thanks.
Give it a try and tell us if you think the result is a valid probability.
"His programming is malfunctioning. It begins! Get your weapons, he's going to become a killbot!!!" - bryangoodrich
Well, the only ones that throw me off are the ones with the ones I subtract 1- etc, etc. When it's given to me in a format of exactly so and so, it's easier to do. From all the questions I have get that has 1- is always based on at least one I have never had at least 3 or 4. I know a probability has to be 1.Originally Posted by Dason
Because I know N is the numbers of trails, X=number of success among n trials, p=probability of success in any one trial. Q= probability of failure if any one trial, q=1-p.
And the answer to my question is 3.998093... And I did that wrong, because the P had to be 4 because that is the probability of the success in any one trial. What my question really is asking, is when I subtract 1- whatever the problem is for this type of solution, is that just for at least 1? Because 1-(Px<1)= to 1-P(X=0).
I got it, nevermind.
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