Compute the difference distribution and determine the probability that it has a value of < 0.
mean of difference distribution = mean1 - mean2
std dev of difference distribution = sqrt(var1 + var2)
note--> var = (std dev)^2
I took statistics many moons ago, and remember performing these calculations, but for the life of me I can't remember what this process is called, or how to do it.
I've got two means and standard devs; how do I determine what the probability that one of the variables will be greater than the other?
Thanks!
Compute the difference distribution and determine the probability that it has a value of < 0.
mean of difference distribution = mean1 - mean2
std dev of difference distribution = sqrt(var1 + var2)
note--> var = (std dev)^2
Manzel,
I am sorry it´s been so long you asked. I believe you what you realy want to know is: Guiven 2 probab. disdtr. functions, what is the probability that one sample from the 1st will be greater than a sample from the other. If that is so, I would like to know it too. If someone read that, and know the answer or where to find it , please replay to both of us.
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