for the first question my answer was 0.006 is that correct by your reckoning?
Originally Posted by el1 and the bottom part of the formula says X!(n-x)! which if x=0 then o*10*9*8.... is that right? for X!*(n-X)! if X=0 then we have 0!*10! 0! is defined to be 1 0!=1 so 0!*10!=1*10*9*8*7*6*5*4*3*2*1=3628800
Originally Posted by el1 for the first question my answer was 0.006 is that correct by your reckoning? after rounding...yes
i think i've got it!! Thanks alot dude! Thank you for your time and patience.
Would you be so kind as to enlighten me about the third question ? Any ideas?
Originally Posted by el1 Would you be so kind as to enlighten me about the third question ? Any ideas? the assumptions for the binomial distribution are independent trials with the same probability of success so for your problem .... each caller needs to be independent from the others and they all have to have the same probability of opting for an operator.
Originally Posted by el1 Would you be so kind as to enlighten me about the third question ? Any ideas? http://childrensmercy.org/stats/defi...s/bin_dist.htm
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