I always start by saying I am only OK with probabilities, but yes your approach seems correct. 5/5 * 4/5 * 3/5 * 2/5 * 1/5 * 5/5.
Hey guys, I want to make sure that I'm working this question correctly. Here goes:
A jar has 5 white balls. A ball is taken out randomly - if it's white, a black ball is inserted instead, and we continue to take balls out. If it's black, we stop.
Whats the probability that we will take 6 balls out until we stop?
So I actually drew it out and treated the event of '6 balls out' as 'we take out all the white ones' and ended up multiplying each probability of taking a white out at each stage.
So - at first we have 5/5 chance of getting a white one out, multiplied by 4/5 chance, 3/5... etc.
Is this a correct way to solve this? I don't know why but it seems iffy really.
Thanks alot!
I always start by saying I am only OK with probabilities, but yes your approach seems correct. 5/5 * 4/5 * 3/5 * 2/5 * 1/5 * 5/5.
Stop cowardice, ban guns!
fiffette (08-25-2013)
Your other post made me revist this one. I believe this is correct, except the last 5/5 would be 0/5 and ignored since it does not make sense to test an impossibility.
Stop cowardice, ban guns!
fiffette (08-27-2013)
Tweet |