If I have a pdf, say X~Uniform[-3,3] and Y= -X, would the pdf of Y be 1/6 [-3,3] ? How would I get the pdf using P(-X < - y) = P(X > y) = 1 - P( X < y) = 1- integral 1/6 from -3,3 so differentiating to get pdf we get -1/6 for [-3,3] but the pdf is negative so I assume my assumption Y is 1/6 is right. Where did I make my mistake?
stephanie (11-29-2013)
Thank you this really helped me
Tweet |