I have a question concerning the following problem:

A hunter has a double-barrelled shotgun. The probability that at least one shot hits the target is 90%. 80% of the time the first shot of the hunter hits the target. 80% percent of the time the hunter hit with the second shot. 75% of the time both shots hit the target.
What is the conditional probability that the second shot hits the target given that the first shot missed the target?

I expect this to be calculated by the Bayes rule or the Bayes theorem using three variables.

I have tried to use a contingency table for the shots (Y means hit, N means miss)

Y1 N1

Y2 75 80

N2 80

What is the process to solve this efficiently for three variables using the formula?
In fact I have not found the application of three variables but tons of other examples