1. ## probability poisson distributed

hi can somebody help me with this question please.

2. ## Re: probability poisson distributed

Hi,

What have you done so far? What is giving you trouble?

3. ## Re: probability poisson distributed

hi,
the lambda seems to be right but the derivation is way too complicated and possibly wrong. The answer should be P(1) + P(2) with the lambda value you found.

regards
rogojel

4. ## Re: probability poisson distributed

Originally Posted by arkeed178
Assuming that the calls are Poisson-distributed, calculate the probability that the consultant receives at least 2 calls during any 30 minute period
"at least 2 calls" isn't that the same as 2 or 3 or 4 or more calls?

So, P(Y>=2) = 1 - {P(Y=0; lambda/2)+P(Y=1; lambda/2)}

Besides, I could not follow the derivation of lambda.

5. ## The Following 2 Users Say Thank You to GretaGarbo For This Useful Post:

arkeed178 (09-02-2014), rogojel (09-01-2014)

6. ## Re: probability poisson distributed

Yes of course, I completely missed it.

7. ## Re: probability poisson distributed

The derivation of lambda is fine. It's messy since they aren't using math tags so sub and superscripts aren't being displayed at all but I'll infer what they meant from context. It's actually possible to derive lambda based on a single equation but you really have to resort to numeric methods to get a solution there. With two equations we can solve directly fairly easily. I would do it slightly differently than the way OP did but their way works just fine as well.

8. ## The Following User Says Thank You to Dason For This Useful Post:

arkeed178 (09-02-2014)

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