+ Reply to Thread
Results 1 to 3 of 3

Thread: Poisson Distribution with two different expected value

  1. #1
    Points: 27, Level: 1
    Level completed: 54%, Points required for next Level: 23

    Posts
    4
    Thanks
    0
    Thanked 0 Times in 0 Posts

    Question Poisson Distribution with two different expected value




    Question:

    Suppose there are number of accidents at location A and location B each day with Poisson Distribution with rate 0.001 and the number of patients during each accident is Poisson distributed with rate 0.1. Find the probability that the number of patients less than 3 in one day.

    Attempt:

    So I did E(N)=0.001\times 0.1=0.0001 and then using this mean to find

    P(X<3)=\sum_{0}^{2}Poi(0.0001)=1

    and I got a value of 1. I am sure this is the wrong answer. Where did it go wrong? I need some help. Thank you!

  2. #2
    TS Contributor
    Points: 12,501, Level: 73
    Level completed: 13%, Points required for next Level: 349

    Posts
    951
    Thanks
    0
    Thanked 103 Times in 100 Posts

    Re: Poisson Distribution with two different expected value

    First thing, I would ask you to double-check the question: Is the question asking for <3 patients in one day or in one year? Is that rate of 0.001 per day or per hour?
    All things are known because we want to believe in them.

  3. #3
    Points: 27, Level: 1
    Level completed: 54%, Points required for next Level: 23

    Posts
    4
    Thanks
    0
    Thanked 0 Times in 0 Posts

    Re: Poisson Distribution with two different expected value


    Yes it is asking for <3. Also I think it is 0.001 per day. Thanks.

+ Reply to Thread

           




Tags for this Thread

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts






Advertise on Talk Stats