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Thread: Null hypothesis at the 5% level of significance

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    Question Null hypothesis at the 5% level of significance




    H0: β1 = β2 = β3 = 0
    H1: At least one of the equalities does not hold

    If I have gotten the answer 5.518 from the formula F k, n- (k +1) = (RSS/ k)/ {SEE/ [n-(k+1)]} , what is my nest step please?

    Does n stand for sample size and k stand for the # of group?

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    Re: Null hypothesis at the 5% level of significance


    To look up your test statistic on the f distribution for k-1 numerator degrees of freedom and n-k denominator degrees of freedom. Go to an F distribution table and it will make more sense.
    Stop cowardice, ban guns!

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