In this case n=400 & p=0.23. Hence q=0.77.
Both np & nq are more than 5. One can use normal approximation of Binomial.
Use mean= np & variance = npq.
Please assist in the following situation:
23% of the adult population possess characteristic X. You conduct a random sample survey of 400 adults.
1. What is the probability that fewer than 50 of your participants exhibit that characterstic?
2. What is the probabiliy that between 50 and 100 of your participants possess X?
3. Would it be unusual for 33% of your group to have X?
Sorry, just not sure how to proceed.
Any ideas would be appreciated.
Thank you.
In this case n=400 & p=0.23. Hence q=0.77.
Both np & nq are more than 5. One can use normal approximation of Binomial.
Use mean= np & variance = npq.
|
|