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Thread: Layperson with a question

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    Re: Layperson with a question




    I wanted to be x% [for example, 99%] sure that I am within y% [for example, 1%] of the expected proportion, for a fair coin which is 0.5.

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    Re: Layperson with a question

    Ok so you know how that 99% plays into it. You said you wanted to be "within 1%". Is there a certain part of the confidence interval equation that is directly related to the "within y%".
    I don't have emotions and sometimes that makes me very sad.

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    Re: Layperson with a question

    Is it, perhaps, " +/- zσ " such that zσ = 0.01?

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    Re: Layperson with a question


    I think I got it. Solve for N in formula for standard error, which was 1/(4σ^2). Solve for zσ by equating it with 0.01 and inserting the z value for 99% (2.58), which results in σ = 0.00387597...

    Finally, sub that back into the first equation to get N = 16641.

    Is that all correct?

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