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2. ## Re:

See "Bayes Theorem" and related posts on TalkStats. P(fault) = .05 = 1- P(no fault). P(favorable | no fault) = .8, P(favorable | fault) = .25. You seek P(fault|favorable).

3. We are looking for P (default / favorable) = 0.05 * 0.8 + 0.95 * 0.25 = 0.2775.

4. What does Bayes Theorem tell you about P(fault|favorable)?

5. Ok, my earlier answer was wrong, further study on Bayes theorem Gives me the following answer.

now let me know if its correct.. Am almost 100&#37; sure that its correct...let me know if otherwise, thaks for your hints...

6. hi zmogggggggggg, can u please verify if the answer is rite?

7. looks good!

8. thnx buddy

9. can i ask u for more questions, if you dont mind?

11. helloooooo

12. ## Re:

13. thanks, after this hint, i think i will be able to solve it, will post the correct answer for your verification

14. 1 more question

On an average 240 airplanes arrive in the O’Hare airport in an hour. What is the probability that
(i) at least one airplane arrives during a ten-minute time span?
(ii) No planes arrive during a 10-minute time span?
(iii) No more than four airplanes arrive during a ten-minute time span?

I think we have to use Poisson Distribution over here, but what is mean here for a 10 minute time span, not able to get it. can you provide me with the hint.

15. zmoggggg can u provide hint for the following

On an average 240 airplanes arrive in the O’Hare airport in an hour. What is the probability that
(i) at least one airplane arrives during a ten-minute time span?
(ii) No planes arrive during a 10-minute time span?
(iii) No more than four airplanes arrive during a ten-minute time span?

I think we have to use Poisson Distribution over here, but what is mean here for a 10 minute time span, not able to get it. can you provide me with the hint.