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Thread: Football (Soccer) Probability

  1. #1
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    Football (Soccer) Probability




    I am having some difficulty in understanding some information that I have been sent.

    I have been given the following information about two football (soccer) teams:

    Team A
    Games Played: 8
    Games where no goal has been scored at half-time: 3 (37.5%)
    Games where 1 or more goals has been scored at half-time: 5 (62.5%)
    Games where no goal has been scored at full-time: 2 (25.0%)
    Games where 1 or more goals has been scored at full-time: 6 (75.0%)

    Team B
    Games Played: 7
    Games where no goal has been scored at half-time: 0 (0.0%)
    Games where 1 or more goals has been scored at half-time: 7 (100.0%)
    Games where no goal has been scored at full-time: 0 (0.0%)
    Games where 1 or more goals has been scored at full-time: 7 (100.0%)

    Teams A and B are about to play each other and I have been given the following information.

    Probability of:
    1) Team A scoring in the first half: 12.50%
    2) Team B scoring in the first half: 57.14%
    3) Probability of 1 more goals being scored in the first half: 62.50%

    I'm struggling to understand these values [1, 2 and 3 above].

    Can anyone enlighten me and explain the calculations?

    [If more information is required, I may have it, so just ask]

  2. #2
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    Re: Football (Soccer) Probability

    Do I take it that no-one else understands how values 1, 2 and 3 were arrived at?

  3. #3
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    Re: Football (Soccer) Probability


    AyF = 3/4 (6 of 8)
    ByF = 1 (7 of 7)

    ByH/ByF = 1
    ByS/ByF = 0

    AyH/AyF = 062/3/4 = 0.82
    AyS/AyF = 038/3/4 = 0.51

    AynF = 1/4
    BynF = 0

    with S i mean the second half, wiht H the first half, F full time
    F = H u S (mutually exclusive)
    AyF = AyH v AyS (also mutually exclusive)
    maybe the data about nF was not complete? i posted this cos perhaps your results are similar

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