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Thread: Hypergeometric Distribution

  1. #1
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    Hypergeometric Distribution




    For part (b), the solution is from the textbook solution from the book. k = 1, so why did they set it up like that? Look at the image to see what I mean. Can anyone explain?
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  2. #2
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    Re: Hypergeometric Distribution

    Following your parameterization,

    N = 25 is the total number of boxes.

    n = 3 is the number of boxes to be sampled.

    k is the total number of defectives, varied in these two parts.

    X is the number of defectives sampled, which is follows a Hypergeometric Distribution.

    In part b), it is correct that k = 1. So the solution should be \binom {1} {1} instead of \binom {3} {1}.

  3. #3
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    Re: Hypergeometric Distribution


    Thank you!

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