The order does not matter, in that you are correct. But the total number of ways to throw the balls is still 3^3 for N=3. The first can hit either of the three baskets. The second can hit either of the three. And the third can also hit either of the three. If I interpret the original question correctly that is.
I got the answer from the person who asked this question as 1-((n-1)/n)^n
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