Hi all,
I'm struggling on a variance of Y question that goes like this:
Let X follow an exponential distribution with a mean of theta. Let Y = X^2. What is the variance of Y?
From what I've gathered, we need to use the definition V(Y) = E(Y^2)-E(Y)^2 and also use integration (by parts??)...
Any help or suggestions would be greatly appreciated.
Thank you for the response!!
So if the distribution for expo is: lambda*e^(-lambda*x)
Does that mean we add X^2 instead of X? Where does integration come in?
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