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Thread: Successive Probabilistic Events

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    Successive Probabilistic Events




    I have some secret code that I need to hack so I know what it is saying. In a single event I pass the problem to four computers in succession. The first computer has an 71.42% percent chance of cracking the code. The first computer then passes the problem on to the second computer that has an 85.71% chance of coming up with the right answer. The passing of the baton continues with computers 3 and 4 that have the same solving abilities as computer #2. Each computer is independent and no algorithms are shared between them. What is the combined system probability that after the forth computer is done and all results are submitted to the supervisor that the code is successfully cracked?

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    Re: Successive Probabilistic Events

    Hi! We are glad that you posted here! This looks like a homework question though. Our homework help policy can be found here. We mainly just want to see what you have tried so far and that you have put some effort into the problem. I would also suggest checking out this thread for some guidelines on smart posting behavior that can help you get answers that are better much more quickly.
    Matt aka CB | twitter.com/matthewmatix

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    Re: Successive Probabilistic Events


    My first attempt is a bit non-conventional:

    HTML Code: 
    (71.42^2+85.71^2+85.71^2+85.71^2)/(71.42+3*85.71)
    Gives me a combined % probability of 82.609.

    I just wanted a second opinion.

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