Seems to me, you're working with a two-tailed hypothesis test. phi is the cumulative density function of whatever distribution you're working with. 8.8 is the test statistic.
It isn't "8.8 times phi"
Can someone please help me understand what this means in plain english?
The p-value = 2 x [1-phi(8.8)] < .001, and the results are highly significant.
Am I multiplying 8.8 times phi? Do I get phi from a table?
Seems to me, you're working with a two-tailed hypothesis test. phi is the cumulative density function of whatever distribution you're working with. 8.8 is the test statistic.
It isn't "8.8 times phi"
Last edited by Buckeye; 09-22-2016 at 01:06 PM.
"I have discovered a truly remarkable proof of this theorem which this margin is too narrow to contain." Pierre de Fermat
kdsan,
It would help if you posted the source or a link to the original content.
Buckeye,
Have you read Fermat's Enigma. Its a great book describing the problem and Andrew Wiles' saga to answer it.
Stop cowardice, ban guns!
I haven't had the chance to read it. But, that quote has been a running joke in a few of my classes when we don't know how to answer a question. I find it funny in that way.
"I have discovered a truly remarkable proof of this theorem which this margin is too narrow to contain." Pierre de Fermat
Attached are screen shots of the problem.
I wasn't too familiar with using the Z-test for comparing proportions. So I looked it up, you find the p-value for the test statistic 8.8 on the standard normal table and multiply it by 2 if you were running a two-tailed test (i.e., Ho: p1 = p2; Ha: p1 not = p2, no directionality on difference).
So you look 8.8 on the standard normal table and minus it from 1 since it in on the left tail. You get 2(1 - 0.99997) for the pvalue.
Stop cowardice, ban guns!
kdsan (10-14-2016)
Thank you So much!!
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