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Thread: Binomial Distribution : Probability equation solution

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    Binomial Distribution : Probability equation solution




    Question :In a binomial distribution for p=.48, q=1-p=.52 find the population size n1 so that P(X>=3)=.95

    My solution :
    P(X>=3)=.95
    can be rewrite as
    P(X=0)+P(X=1)+P(X=2)=.05 ------------------------------------------ eq(1)
    but i am un able to solve the above equation for n1,

    Is there any way to solve the equation (1) or is there any alternate solution?

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    Re: Binomial Distribution : Probability equation solution

    Your equation is correct, but you need to "plug in" the probabilities for X=0, X=1, and X=2. You need to use this: \sum_{x = 0}^n {n \choose{x}} p^x (1-p)^{n-x}

    Assuming you did this, I understand your frustration. The equation is a little messy. Still pondering it.
    Last edited by Buckeye; 09-29-2016 at 02:07 PM.
    "I have discovered a truly remarkable proof of this theorem which this margin is too narrow to contain." Pierre de Fermat

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    Re: Binomial Distribution : Probability equation solution


    hi,
    trial and error? There are only a few possible choices for n.
    regards

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