Hello all,

I have this problem:

X~N(mu, sigma^2)

We know that:

P(79-a<=X<=79+b)=0.6463
P(X>=79+b)=2P(X<=79-a)

Find P(X<=79-a)

I have solved it and got 0.1179.

I wanted to ask you if I can also find the values of a and b, or perhaps the mean and standard deviation of X. I tried, and all I could manage was to write a+b in meaning of standard deviations (1.8727 standard deviations). Is it possible to find something more accurate?

Thank you in advance !