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Let X follows N (mean=65.3 and sd 10.3).
Now you have to calculate K such that P(X <K )=.81
Convert into Standard Normal
P[ (X-mean)/sd < (K-mean)/sd] =.81
P[Z <(K-mean)/sd] =.81
Now from normal table calculate Za such that P[Z<Za]=.81
then solve K.
HI
can someone help me set this up to solve. i know i had missed this on one my previous exam, and trying to study for tomorrow final exam.
scores on a test are normally distributed with a mean of 65.3 and a standard deviation of 10.3. find p 81 (percentile 81) which separates the bottom 81% from the top 19%,
the answer is 74.4
how do i sovle for the percentile.
Let X follows N (mean=65.3 and sd 10.3).
Now you have to calculate K such that P(X <K )=.81
Convert into Standard Normal
P[ (X-mean)/sd < (K-mean)/sd] =.81
P[Z <(K-mean)/sd] =.81
Now from normal table calculate Za such that P[Z<Za]=.81
then solve K.
In the long run, we're all dead.
sorry but
so far i got
6.3398< kmean = 834.30
then I am not so sure what to do next
See these examples in the link .. it may help.
http://cnx.org/content/m16977/latest/
In the long run, we're all dead.
First find Znormal value that corresponds to area from -infinity to +Z as 0.81 (given).
Now this value of Z = (X-Mean)/ standard deviation.Since mean & s.d. are known you can find X which is unknown.
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