problem with a Combination rule word problem

[David_langstaff]

I am having a little trouble finding the answer to this word problem

If you drew three cards form a standard deck without replacement, what would be the probability of drawing to kings and a queen? (KKQ or KQK or QKK)
I am using the Combination rule because the order of the cards does not matter.

nCr=n!/(n-r)!r! = 52! / (52-3)!3! = 52! / 49!3! = 22,100 So there are 22100 ways that that you could get the combination of three cards. But that does't answer the question of the probaility of getting two King and a Queen out of those.
One thought was to take the cubed root of the 22100. But I really have no idea, is there a easier way?

[spengel]

I believe if you're using a combination, then the 22,100 ways to choose three cards from a deck of 52 will be in the denominator of your problem.

For the numerator, to get 2 Kings, there are 4 Choose 2, or 6 ways of getting 2 Kings. Then there are 4 Choose 1, or 4 ways of getting 1 Queen.

So, I think the probability of getting 2 Kings and 1 Queen is:

[6 X 4]/22100 = 24/22100 = 0.00109