# confidence interval

1. ### Sample Estimate expression in Brunner-Muenzel test with R (lawstat)

Dear Talk Stats Community, I try to provide a reasonable interpretation of Sample Estimate expression P(X<Y) + .5*P(X=Y), which is shown as an output for BM-test in R (lawstat package). I am confused with the relationship between the following three probabilities: P(X<Y), P(X>Y), P(X=Y)...
2. ### Minimum Accepted Sample Size for Tolerance Interval (confidence interval)

Hi, I'm using the tolerance interval function in minitab, my sample size is limited to 7 (the parts are expensive blah blah) I've heard to be statistically significant a sample size of 30 is recommended but in practice how low can I go for sample size when using a confidence / tolerance...
3. ### Difference-in-differences in Health Economics Research

Hi, I'm doing a difference-in-differences analysis of a health policy intervention. Health clinics are paid for the percentage of eligible patients who they give the right treatment to. The clinics are measured/paid separately for each type of treatment indicator. One year, some of the...
4. ### T-testing of two samples(question about t-statistic)

Hi have two questions regarding an t-test assignment i did. Basically the null hypothesis was that if sample x2 differed 35 off the mean from sample x1 was it reject-able? The mean of sample x is 395 The mean of sample ý is 435. So the issue is that i think the nominator for the t-statistic...
5. ### Constructing intervals VS hypothesis testing?

Hi folks, let me briefly anticipate that I am a total newby to the magical world of statistics. So, right now I'm preparing for a "quantitative methods for economics" test, but while doing my exercises I found myself wondering about what could be very stupid things. here's the thing: I had...
6. ### How can I find an interval estimate for the mean of a Weibull distribution?

I have a sample of n = 75 taken from a Weibull distribution and have computed mle estimates for the scale a and shape b parameter. The mean of a Weibull distribution (2 parameter) is given as u = a^(-1/b)*gamma(1+ 1/b) In which case I can find an estimate for u by simply plugging in the mle...