This is how I am trying to calculate it:

Over all goal is to calculate all possible wins / all possible combinations

a-f are all wins

(a) (odds of exactly 5 1s)

(1/6^5) +

(b) (odds of exactly 4 1s and anything for remaining 1 dice)

((1/6^4)*5) +

(c) (odds of exactly 3 1s and anything for remaining 1 dice)

((1/6^3)*10) +

(d) (odds of exactly 2 1s and anything for remaining 1 dice)

((1/6^2)*10) +

(e) (odds of exactly 1 1) times (odds of a pair (not 1's) out of remaining 4)

((1/6^1)*5)*(???????) +

(f) (odds of exactly 0 1's times (odds of three of a kind (not 1's) out of remaining 5) =

???????

/

all possible combinations is 6^5, or is it (6+5-1)! / ((5!)(6-1!)) ???

=

????

The guy claimed it was 1/3 but I really need to prove him wrong. Thank you so much for anyone who even read this!!!:wave: