Hi,
I'm terrible at statistics, i hope someone can help.
A ship sank into the sea and is now laying in a fixed but uknown position on the bottom of the sea in either British or foreign wanters. The probability that the ship is in British waters is 0.7. An extensive search is planned through the British sea to find the ship. If the ship is found in british waters, then the probability that it will be found by such a search is 0.8 (while the probability that it is overlooked is 0.2)
a) Give the probability that the ship will be found through british water?
Does bayes theorem apply in here?
A= ship is in british waters (0.7)
B = ship will be found (0.8)
P(A|B) = P(A^B)/P(B) = 0.56/0.8 = 0.7
b) if the ship is not found, what is the probability that ship is situated in british waters.
1 - 0.7 = 0.3
Is this correct?
I'm terrible at statistics, i hope someone can help.
A ship sank into the sea and is now laying in a fixed but uknown position on the bottom of the sea in either British or foreign wanters. The probability that the ship is in British waters is 0.7. An extensive search is planned through the British sea to find the ship. If the ship is found in british waters, then the probability that it will be found by such a search is 0.8 (while the probability that it is overlooked is 0.2)
a) Give the probability that the ship will be found through british water?
Does bayes theorem apply in here?
A= ship is in british waters (0.7)
B = ship will be found (0.8)
P(A|B) = P(A^B)/P(B) = 0.56/0.8 = 0.7
b) if the ship is not found, what is the probability that ship is situated in british waters.
1 - 0.7 = 0.3
Is this correct?