A carton holds 18 eggs. If only 3 eggs are fertile, what is the probability of randomly selecting 2 eggs that are fertile if the selected eggs are not replaced?

A) 3/28

B) 9/64

C) 1/4

D) 3/4

I was under the impression that the correct answer would be (3/18)*(2/17) = 1/51, but I have reason to believe the 'correct' answer is 1/4.

Either I'm missing something (Probability > 0.5) or the 'correct' answer is wrong. Is there a justification/formula that indicates the answer is 1/4?

Thanks for any help anyone can provide.

Regards,

John M.