Combinations average

#1
I have 6 averages, 365, 406, 420, 416, 434, 435. How many ways can you split the group to have two groups of 3 with similar averages? The closer the average, the better. Each average can only be in one group.
 

rogojel

TS Contributor
#2
This will depend on how similar should similar groups be to be considered similar :)? You have C(6,2) =6!/4!*2!=15 different groupings, the similarity in each should be easy to calculate.