NOW SOLVED. SPECIAL THANKS TO rogojel and con-tester. This is probably a simple problem, but I have been through my 8 counting rules about different arrangements, etc, and cannot find one that applies. If 4% of the population is Christian and 19% are Jewish, what is the probability, when selecting a forum of 9 people, that 3 Christians and 6 Jewish people are chosen? This is assuming random selection (ie every element of the population has an equal chance of being selected). Now I cannot see any obvious equiprobable permutations or equiprobable sets (combinations). For instance a permutation that has more Jews in seems more probable than one with more Christians so I cannot use number of permutations. If I start with probablity of Jew and not (other or Christian)x(probability..)etc... I get a complicated solution that I need the number of permutations for, etc. Does someone know of a good method (not necessarily with an answer)?