***I am getting stuck on finding the sample proportion.

p= #successes/ n

This is how I tried to find p-value:

Step I

H sub naught: p is less than or equal too .28

H sub alternative p is greater than .28

Step II

Signifance level= .05

Step III

Calculate standard error for Z statistic manaully and w/Megastat.

Manuall I tried .32*130= 41.6 for p

inputting 41.6 as the sample proportion into the Z equation my results were:

1051.39 referenced this too the z table, z=.27 (.5 -.27=.23)

Megastat returned z= 1.02

Using Megastat results z=1.02 Z table area=.3461

.5-.3461= .1539 (manually able to compute using z=1.02 from Megastat)

***Here in lies my confusion, using megastat it gives the return

p value as .1549

z=1.02

the choices given for p value are:

0.1539

0.3078

0.3461

0.1635

??? Why the difference of p value .1549 and the answer provided .1539.

Trying to to figure out why this is

I know t test you can find rejection region but not p value

the z test I ought to be able to find rejection region and p value

Thank you. Jesse.